Question

Determine the nature of roots of the given equation from its discriminant.

$x^2+3\sqrt{2}x-8=0$

• A. Real and unequal
• B. Real and equal
• C. One real and one imaginary
• D. Both imaginary

Answer 1

The correct option is A Real and unequal

Discriminant of the equation $x^2-3\sqrt{2}x-8=0$

$D=b^2-4ac$

$D=(-3\sqrt{2}{)}^2-4\times 1\times (-8)$

$=18+32$

$=50$

Since, $D>0$ thus, roots are real and unequal