Question

Determine the nature of the roots of the following quadratic equations
$2x^2+6x+3=0$

Answer 1

Consider the given equation.

$2x^2+6x+3=0$ …….. (1)

Therefore,

$x=\frac{-6\pm \sqrt{36-4\times 2\times 3}}{2\times 2}$

$x=\frac{-6\pm \sqrt{36-24}}{4}$

$x=\frac{-6\pm \sqrt{12}}{4}$

$x=\frac{-3\pm \sqrt{3}}{2}$

So, the roots are real and distinct.