Question

Determine the nature of the roots of the follwoing quadratic equation :

$2x^2-6x+3=0$

Answer 1

$2x^2-6x+3=0$

This is of the form $a{x}^2+bx+c=0$, where $a=2,b=-6,c=3$.

$D=b^2-4ac=36-24=12>0$

Therefore, the given equation has real unequal roots.