Question

Determine the nature of the roots of the given quadratic equation
$4x^2-4x+1=0$

Answer 1

The given equation is $4x^2-4x+1=0$

Here, $a=4,b=-4,c=1$

$\therefore D=b^2-4ac={(-4)}^2-4\times 4\times 1=0$

since $D=0$, the roots of the given equation are real and equal.