Question

Determine the nature of the roots of the given quadratic equation
$x^2-4x+4=0$

Answer 1

The given equation is $x^2-4x+4=0$

Here, $a=1,b=-4,c=4$

$\therefore D=b^2-4ac={(-4)}^2-4\times 1\times 4=0$

Since $D=0$, therefore roots of the given equation are real and equal