Determine the no. of terms in the expansion of (a+b+c+d)5 and (1+a+a2+a3)5
No. of terms in expansion of (a+b+c+d)5 = Number of solution of (a + b + c + d) = 5, 8C3 = 56
No. of terms in expansion of (1+a+a2+a3)5=(5×3)+1=16
Hence option (a)
The first three terms in the expansion of (1+a)n are t1=1,t2=−18,t3=144.
Use the general term to determine a and n.