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Question

Determine the no. of terms in the expansion of (a+b+c+d)5 and (1+a+a2+a3)5

A
56, 16
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B
32, 24
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C
165, 32
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D
32, 32
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Solution

The correct option is A 56, 16

No. of terms in expansion of (a+b+c+d)5 = Number of solution of (a + b + c + d) = 5, 8C3 = 56

No. of terms in expansion of (1+a+a2+a3)5=(5×3)+1=16

Hence option (a)


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A+B+C=N (N Fixed)
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