Determine the number nearest to $110000$ but greater than $100000$ which is exactly divisible by each of $8, 15$ and $21$ .

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Solution

$8, 15, 21$
LCM $(8, 15, 21) = 840$
multiple of $840$ near to $110000$
$\Rightarrow 840 \times 3 \times 43$
$= 108360 + 840 + 840$
$= 110040$

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Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.

8,15,21LCM (8,15,21)=840multiple of 840 near to 110000⇒840×3×43=108360+840+840=110040

Determine the number nearest to $110000$ but greater than $100000$ which is exactly divisible by each of $8, 15$ and $21$ .

$8, 15, 21$
LCM $(8, 15, 21) = 840$
multiple of $840$ near to $110000$
$\Rightarrow 840 \times 3 \times 43$
$= 108360 + 840 + 840$
$= 110040$