Question

Determine the number of hydrogen atoms in 360 g of glucose. Given, the molecular formula of glucose is C${}_6$H${}_1$${}_2$O${}_6$.

• A. $12\times 6.022\times {10}^{23}$
• B. $10\times 6.022\times {10}^{23}$
• C. $24\times 6.022\times {10}^{23}$
• D. $2\times 6.022\times {10}^{23}$

Answer 1

The correct option is C $24\times 6.022\times {10}^{23}$

Molecular formula of glucose =
C${}_6$H${}_1$${}_2$O${}_6$
Molar mass of glucose = $(6\times 12)+(12\times 1)+(6\times 16)$ = $180g$

Number of moles of glucose = $\frac{Givenmass}{Molarmass}$
Thus, number of moles of glucose = $\frac{360}{180}=2$ moles
Number of molecules in 1 mole of glucose = $6.022\times {10}^{23}$
Number of molecules of glucose in 2 moles = $2\times 6.022\times {10}^{23}$

Now, the number of hydrogen atoms in 1 molecule of glucose = 12
Thus, number of hydrogen atoms in$2\times 6.022\times {10}^{23}$
molecules of glucose = $12\times 2\times 6.022\times {10}^{23}$ = $24\times 6.022\times {10}^{23}$