Determine the oxidation number of Cr in the $C r_{2} {(S O_{4})}_{3}$ compound :

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Solution

The correct option is B 3
$C r_{2} (S O_{4})_{3}$

Oxidation number= $2 x + (3 \times - 2) = 0$

$\Rightarrow 2 x = 6$

$\Rightarrow x = 3$

Hence the correct option is B.

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