Question

Determine the percentage composition of each atom in the molecule of ${Na}_2{CO}_3$.

Answer 1

The percentage composition of each atom in molecule $=(no.ofatoms)\times \frac{\left(Atomicmassofelement\right)}{\left(Molarmassofelement\right)}\times 100$

$\%Na=\frac{2\times 23}{106}\times 100=43.39\%\approx 43.4\%$

$\%C=\frac{12}{106}\times 100=11.32\%$

$\%O=\frac{3\times 16}{106}\times 100=45.28\%$