Determine the percentage of oxygen in ammonium nitrate.

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Solution

Step 1. Ammonium nitrate ( ${NH}_{4} {NO}_{3}$ )
Step 2. Mass percentage $= \frac{Atomic weight}{Total molecular weight} \times 100$
Step 3. Molecular weight of ${NH}_{4} {NO}_{3}$
$= 4 g + 28 + 48$
$= 80 g / mole$
Mass percentage of oxygen (O) in ammonium nitrate
$= \frac{48}{80} \times 100$
$= 60 %$
Therefore, percentage of oxygen in Ammonium nitrate is $60 %$

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Similar questions

A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH₄NO₃ $\overset{}{\to}$ N₂O + 2H₂O
(i) What volume of dinitrogen oxide is produced at the same time as 8.96 litres of steam?
(ii) What mass of ammonium nitrate should be heated to produce 8.96 litres of steam?
(Relative molecular mass of ammonium nitrate is 80.)
(iii) Determine the percentage of oxygen in the ammonium nitrate. (O = 16)

Calculate the percentage composition of oxygen in lead nitrate [Pb(NO₃)₂].
(Pb = 207, N = 14, O = 16)

A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP).

NH₄NO₃ → N₂O +2H₂O

Determine the percentage of oxygen in ammonium nitrate. (O = 16)

Q. If the relative molecular mass of ammonium nitrate is 80, the percentage of nitrogen and oxygen in ammonium nitrate is:

[N = 14, H = 1, O = 16]

Calculate the percentage of nitrogen and oxygen in ammonium nitrate.[Relative molecular mass of molecular nitrate is 80 ,H= 1,N =14, O= 16].

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Determine the percentage of oxygen in ammonium nitrate.

Step 1. Ammonium nitrate (NH4NO3) Step 2. Mass percentage =AtomicweightTotalmolecularweight×100Step 3. Molecular weight of NH4NO3 =4g+28+48 =80g/moleMass percentage of oxygen (O) in ammonium nitrate =4880×100 =60%Therefore, percentage of oxygen in Ammonium nitrate is 60%