Question

Determine the pH value of $0.001M$ acetic acid solution if it is $2$% ionised at this concentration. How can the degree of dissociation of this acetic acid solution be increased?

Answer 1

$c=0.001M$

$\left[H^{+}\right]=C\alpha$
$=0.001\times 2$
$=0.002$

pH $=-\log \left[H^{+}\right]$
$=-\log \left[0.002\right]$

$pH=2.69897$