Determine the point of application of force, when forces of $20 N$ and $30 N$ are acting on a rod as shown in figure

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Solution

Net force acting on the rod, $F_{r e l} = 10 N$
Net torque acting on the rod about point C is
$τ_{c} = (20 \times 0) + (30 \times 20) = 600$ clockwise
Let the point of application be at a distance $x$ from point C
$600 = 10 x \Rightarrow x = 60 C M$
Therefore, $70 C M$ from $A$ is the point of application of force.

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Determine the point of application of force, when forces of 20N and 30N are acting on a rod as shown in figure

Net force acting on the rod, Frel=10NNet torque acting on the rod about point C isτc=(20×0)+(30×20)=600 clockwiseLet the point of application be at a distance x from point C600=10x⇒x=60CMTherefore, 70CM from A is the point of application of force.

Determine the point of application of force, when forces of $20 N$ and $30 N$ are acting on a rod as shown in figure