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Question

Determine the point on the graph of the linear equation 2x+5y=19 whose ordinate is 1½ times of its abscissa

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Solution

Given linear equation is
2x + 5y = 19 … (1)

Given that ordinate is 1 ½ times its abscissa
That is y = 3x /2

Hence equation (1) becomes
2x + 5(3x /2) = 19
19x/2 = 19
Therefore, x = 2

y = 3x/2 = (3 × 2)/2 = 3

Thus the point on the graph is (2, 3).

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