wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Determine the ratio of perimeter of 2nd and 3rd Bohr orbit in He+ atom (Z=2).

A
94
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
169
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
916
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
49
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 49
The Bohr radius of the nth orbit is,

rn=0.529(n2Z) ˚A

rnn2Z

r2r3=(n2n3)2=(23)2=49 [ Z=same]

Now, perimeter of the nth bohr radius is,

Pn=2πrn Pnrn

Let P2 and P3 be the perimeter of the 2nd and 3rd bohr orbit, respectively.

P2P3=r2r3=49

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.
Why this question ?
Key concept :
The bohr radius of the nth orbit is,rn=0.53(n2Z) ˚A

rnn2Z


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Perception of Sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon