Question

Determine the reaction at support A ad B of loaded beam shown in Fig.1 ,

Answer 1

Drawing free body diagram of the loaded beam.

As the loaded beam is stationery upward and downward for us should balance each other

Thus, $R+R^{\prime }=40+60=100kN$ - $\left(1\right)$

Now the force applied by the beam will be equally distributed among the two supports and the hence the reaction force by the two support will also be equal, i.e, $R=R^{\prime }$

from $\left(1\right)$

$2R=100kN$

$\to R=50kN$

Hence the reaction at support $A$ and $B$ will be equal to $50kN$ each.