Determine the smallest natural number which when divided by $12, 16, 24$ and $36$ leaves remainder $7$ in each case.

Open in App

Solution

Find L.C.M. of $12, 16, 24, 36$
L.C.M. of $12, 16, 24, 36$ $= 2 \times 2 \times 2 \times 2 \times 3 \times 3 = 144$
The required least number will be $= 144 + 7 = 151$
Therefore, smallest natural number which when divided by $12, 16, 24$ and $36$ leaving remainder $7$ in each case is $151$ .

Suggest Corrections

Similar questions

Find the smallest number which when divided by $18, 12$ and $24$ leaves remainder $16, 10$ and $22$ respectively.

Find the least number which when divided by $12, 16, 24$ and $36$ leaves a remainder $5$ in each case.

Determine the smallest natural number , which when divided by $12, 16, 24$ leaves remainder $7$ in each case.

12, 16, 24

36

7

Determine the smallest and greatest number which when divided by 3, 4 and 5 leaves remainder 2 in each case

Join BYJU'S Learning Program