Determine the speed with which block B rises up (as shown in the figure) if the end of the cord at A is pulled down with a speed of 2 m/s.
0.5 m/s
Okay
Let's take ceiling as reference point
Marking position of pulley C, D and A
Assuming direction of velocity of C and E
There are two strings
Lets find their length
(xA−xC) + (xE−xC) + xE = l1
⇒ xA + 2xE − 2xC = l1
Differentiating with t we get
vA − 2vE − 2vC = 0
∵ as string length is decreasing according to our assumed direction of velocity.
vA = 2vE + 2vC ....(1)
Now for the second string
xC + xE = l2
differentiating
vC − vE = 0
as xE is decreasing by our assumed direction of velocity
vC = vE ....(ii)
substituting this in eg (i) we get
vA = 4vE
The velocity of block and pulley are same
⇒ vA = 4vB
vA = 2 m/s
vB = 0.5 m/s in the upward direction.