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EMF

Determine the...

Question

Determine the standard emf of the cell and standard free energy change of the cell reaction $Z n | Z n^{2 +} | | N i^{2 +} | N i$ . The standard reduction potentials of $Z n^{2 +} | Z n$ and $N i^{2 +} | N i$ half cells are $- 0.76 V$ and $- 0.25 V$ respectively.

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Solution

$Z n | {Z n}^{+ 2} | | {N i}^{+ 2} | N i$
Given:-
$E_{{Z n}^{+ 2} | Z n} = - 0.76 V$
$E_{{N i}^{+ 2} | N i} = - 0.25 V$
$n = 2$
Therefore,
Standard emf of cell $({E^{\circ}}_{c e l l}) = {E^{\circ}}_{R} - {E^{\circ}}_{L}$
$\Rightarrow {E^{\circ}}_{c e l l} = - 0.25 - (- 0.76) = 0.51 V$
Now, standard free energy change is given as-
$Δ G^{\circ} = - n F {E^{\circ}}_{c e l l}$
$\Rightarrow Δ G^{\circ} = - 2 \times 96500 \times 0.51 = 98430 J$

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