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Question

Determine the sum of first 25 terms of an A.P whose second term is 7 and 27seventh
term is 157

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Solution

Let a be the first term and d be the common difference in an A.P
Given:a+d=7 ....(1) and a+26d=157 ....(2)
Eqn(2)Eqn(1)=a+26dad=1577=150
25d=150
d=15025=6
We have a+d=7a=7d=76=1
S25=252[2×1+(251)6]
=25[1+25×3]=25×76=1900

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