Question 185
Determine the sum of the four numbers as given below.
(a) Successor of 32
(b) Predecessor of 49
(c) Predecessor of the predecessor of 56
(d) Successor of successor of 67
We know that, for getting the successor of a number, we add 1 in that number and for getting the predecessor, we subtract 1 from that number.
(a) Successor of 32 = 32 + 1 = 33
(b) Predecessor of 49 = 49 -1 = 48
(c) Predecessor of the predecessor of 56 = 56- 1 - 1= 54
(d) Successor of successor of 67 = 67+ 1+ 1 = 69
Now, required sum = 33 + 48 + 54 + 69 = 204