Determine the surface tension forces in case a plate of radius 10cm is placed on a water surface (surface tension of water = $7 \times 10^{- 2} N / m; π = \frac{22}{7})$

4400 dyne

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6600 dyne

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8800 dyne

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2200 dyne

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Solution

The correct option is A
4400 dyne

$F = 2 π r T = 4400 d y n e$
$T = 7 \times 10^{- 2} N / m . r = 10 c m$

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Similar questions

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The force required to take away a flat plate of radius 4 cm from the surface of water is (surface tension of water = 70 dyne/cm)

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and breadth

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Determine the surface tension forces in case a plate of radius 10cm is placed on a water surface (surface tension of water = 7×10−2N/m;π=227)

The correct option is A 4400 dyne F = 2πrT = 4400 dyne T = 7×10−2 N/m. r = 10 cm

Determine the surface tension forces in case a plate of radius 10cm is placed on a water surface (surface tension of water = $7 \times 10^{- 2} N / m; π = \frac{22}{7})$

The correct option is A
4400 dyne

$F = 2 π r T = 4400 d y n e$
$T = 7 \times 10^{- 2} N / m . r = 10 c m$