Determine the time interval, in hours, required to fill a $1 m^{3}$ volume at the same rate.

1.01

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Solution

The correct option is D $1.01$
Here, $1 m = 39.37$ inch
So, $1 m^{3} = (39.37)^{3} = 6.1 \times 10^{4}$ cubic inch
Now, $1$ gal $= 231$ cubic inch
so, $35$ gal $= 231 \times 35 = 8085$ cubic inch
Thus, $1$ cubic inch $= 35 / 8085 = 4.33 \times 10^{- 3}$ gal
Hence, $1 m^{3} = 6.1 \times 10^{4} \times 4.33 \times 10^{- 3} = 264.07$ gal
Thus, the required time interval is $t = \frac{8}{35} \times 264.07 = 60.36 m i n = 60.36 / 60 = 1.01 h r$

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Determine the time interval, in hours, required to fill a 1m3 volume at the same rate.

Determine the time interval, in hours, required to fill a $1 m^{3}$ volume at the same rate.