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Question

Determine the value of equilibrium constant (KC for the reaction
AA2(g)+B2(g)2AB(g) If 10 moles of A2:15 moles of B2 and 5 moles of AB are placed in a 2 litre vessel and allowed to come to equilibrium. The final concentration of AB is 7.5 M

A
4.5
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B
1.5
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C
0.6
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D
None of these
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Solution

The correct option is A 4.5
A2(g)+B2(g)2AB(g)
Initial conc.10/215/25/2
at eqn 5x7.5x2.5+2x
2.5+2x=7.5
x=2.5
Kc=(7.5)22.5×5=4.5

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