Determine the value of k for which the given system of equations has a unique solution: x−ky=2,3x+2y=−5
Condition for the unique solution is a1a2≠b1b2 Given lines
x−ky=2, and 3x+2y=−5
⇒13≠−k2 ⇒k≠−23
For what value of k does the system of equations x+2y=3,5x+ky+7=0 have(i) a unique solution,(ii) no solution?
Also,show that there is no value of k for which the given system of equations has infinitely many solutions.