Determine the value of median from the following data with the help of: (i) 'less than' and 'More than' Ogive Method; (ii) 'Less than' Ogive method; (iii) 'More than' Ogive method.

Marks 0−10 10−20 20−30 30−40 40−50 50−60

No. of Students 10 15 25 30 10 10

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Solution

Marks
(Class Interval) Students
(f) Less than
c.f. More than
c.f.

0 − 10
10 − 20
20 − 30
30 − 40
40 − 50
50 − 60 10
15
25
30
10
10 10
25
50
80
90
100 100
90
75
50
20
10

From the point of intersection, a perpendicular is drawn on the x-axis. This line cuts the x-axis at 30. Hence, the median is 30 marks

Median = 30 marks

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Marks (Class Interval)	Students (f)	Less than c.f.	More than c.f.
0 − 10 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60	10 15 25 30 10 10	10 25 50 80 90 100	100 90 75 50 20 10