Determine the value of the following
${log}_{25} 5$

Open in App

Solution

$l o g_{25} 5 = \frac{l o g 5}{l o g 25} = \frac{l o g 5}{l o g 5^{2}} = \frac{l o g 5}{2 l o g 5} = \frac{1}{2}$

Suggest Corrections

Similar questions

{log}_{3} 5 \times {log}_{25} 9

{l o g}_{25} \sqrt{5} \times {l o g}_{3} \frac{1}{5}

{log}_{2} (5 \times 2^{x} + 1), {log}_{4} (2^{1 - x} + 1), 1

x

{log}_{2} 5 - 4 \sum k = 1 {log}_{2} (sin \frac{k π}{5}) = \frac{p}{q},

p

q

p + q

log 2 = 0.3010

log 3 = 0.4771

log 25

Join BYJU'S Learning Program