Question

Determine the values of $p$ for which the quadratic equations $2x^2+px+8=0$ has real roots.

Answer 1

$2x^2+px+8=0$

$b^2-4ac>0$

$p^2-4\left(2\right)\left(8\right)>0$

$p^2-64>0$

$\therefore p=\pm 8$