Determine whether $50 c m, 80 c m, 100 c m$ can be the sides of a right triangle or not.

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Solution

As we know that, in a right angled triangle, the square of largest side is equal to the sum of square of other two sides.
Therefore,
${(100)}^{2} = 10000$
${(50)}^{2} + {(80)}^{2} = 2500 + 6400 = 8900 \neq 10000$
Hence the given sides can not be the sides of right angled triangle.

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Determine whether 50 cm,80 cm,100 cm can be the sides of a right triangle or not.

As we know that, in a right angled triangle, the square of largest side is equal to the sum of square of other two sides.Therefore,(100)2=10000(50)2+(80)2=2500+6400=8900≠10000Hence the given sides can not be the sides of right angled triangle.

Determine whether $50 c m, 80 c m, 100 c m$ can be the sides of a right triangle or not.

As we know that, in a right angled triangle, the square of largest side is equal to the sum of square of other two sides.
Therefore,
${(100)}^{2} = 10000$
${(50)}^{2} + {(80)}^{2} = 2500 + 6400 = 8900 \neq 10000$
Hence the given sides can not be the sides of right angled triangle.