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Question

Determine whether each of the following relations are reflexive, symmetric and transitive:
(ii) Relation R in the set N of natural numbers defined as
R = {(x, y): y = x + 5 and x < 4}

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Solution

Here, A=N, the set of natural numbers and R={(x,y);y=x+5,x<4}
={(x,x+5):xϵN and x < 4}

={(1,6),(2,7),(3,8)}
(a)For reflexive x,xϵRx putting y=x,xy+5(1,1)/ϵR. So, R is not reflexive.

(b)For symmetrical (x,y)ϵR(y,x)ϵR putting y =x+5, then xy+5(1,6)ϵR but (6,1)/ϵR. So, R is not symmetric.

(c)For transitivity (x,y)ϵR,(y,z)ϵR(x,z)ϵR if y =x+5, z=y+5, then zx+5. Since, (1,6)ϵR and there is no order pair in R which has 6 as the first element same in the case for (2,7)and (3,8). So, R is not transitive.


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