(i)
Consider the values of a=1 and b=2 for the provided equation.
1*2=1−2 =−1
For the given case, such that a,b∈ Z + , the function provides the value that is not defined in its range.
Thus, the function * is not a binary operation.
(ii)
Consider the values of a=1 and b=2 for the provided equation.
1*2=1( 2 ) =2
For the given case such that a,b∈ Z + , the function provides the value that is defined in its range. So it is deduced that the function * have a unique element ab∈ Z + . It means that the function * carries each pair ( a,b ) to a unique element a*b=ab in Z + .
Thus, the function * is a binary operation.
(iii)
Consider the values of a=1 and b=2 for the provided equation.
1*2=1 ( 2 ) 2 =4
For the given case such that a,b∈R , the function provides the value that is defined in its range. So it is deduced that the function * have a unique element a b 2 ∈R . It means that the function * carries each pair ( a,b ) to a unique element a*b=a b 2 in R .
Thus, the function * is a binary operation.
(iv)
Consider the values of a=1 and b=2 for the provided equation..
1*2=| 1−2 | =| −1 | =1
For the given case such that a,b∈ Z + , the function provides the value that is defined in its range. So it is deduced that the function * have a unique element | a−b |∈ Z + . It means that the function * carries each pair ( a,b ) to a unique element a*b=| a−b | in Z + .
Thus, the function * is a binary operation.
(v)
Consider the values of a=1 and b=2 for the provided equation.
1*2=1 =1
For the given case such that a,b∈ Z + , the function provides the value that is defined in its range. So it is deduced that the function * have a unique element a∈ Z + . It means that the function * carries each pair ( a,b ) to a unique element a*b=a in Z + .
Thus, the function * is a binary operation.