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Question

Determine whether the following is even or odd
f(x)=x2−|x|

A
f(x) is even
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B
f(x) is odd
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C
f(x) is neither even nor odd
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D
f(x) is even and periodic
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Solution

The correct option is A f(x) is even
f(x)=x2|x| is symmetric about y-axis.
Therefore, f(x)=f(x)
Hence, it is an even function.

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