You visited us 1 times! Enjoying our articles? Unlock Full Access!

Spontaneity

Determine whe...

Question

Determine whether the following reaction will be spontaneous or nonspontaneous under standard conditions.
$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s), Δ H^{0} = - 219 k J, Δ S^{0} = - 21 J K^{- 1}$ .

Open in App

Solution

$△ G$ = $△ H$ - T $△ S$
Where $△ G$ is change in Gibbs free energy
$△ H$ is change in enthalpy
$△ S$ is entropy change .
Any reaction is spontaneous if $△ G$ is negative for that reaction.
T is 273K (standard conditions)

$△ G$ = -219000 - 273 ×(- 21)
$△ G$ = -213267 J
Since $△ G$ is negative hence reaction is spontaneous .

Suggest Corrections

Similar questions

Z n (s) + {C u}^{2 +} (a) ⟶ {Z n}^{2 +} (a q) + C u (s) △ H^{0} = - 219 k J, △ S^{0} = - 21 {J K}^{- 1} (S p o n t a n e o u s)

Z n ∣ ∣ {Z n}^{2 +} (a q) ∣ ∣ ∣ ∣ {C u}^{2 +} (a q) ∣ ∣ C u

{C u}^{2 +} + {2 e}^{-} ⟶ C u, E^{\circ} = + 0.35 V

{Z n}^{2 +} + {2 e}^{-} ⟶ Z n, E^{\circ} = - 0.763 V

Z n | Z n^{2 +} (a q) (1.0 M) | | C u^{2 +} (a q) (1.0 M) | C u

+ 0.35 V

2 e^{-} + C u^{2 +} (a q) \to C u^{2 +} (a q) (1.0 M) | C u

+ 0.35 V

2 e^{-} + C u^{2 +} (a q) \to C u

- 0.763 V

2 e^{-} + Z n^{2 +} (a q) \to Z n

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E^{\circ}

Z n (s) | Z n^{2 +} 1 M (a q .) ∥ C u^{2 +} 1 M (a q .) | C u (s)

1.10 V

25^{\circ} C

Z n (s) + C u^{2 +} (a q .) ⇌ Z n^{2 +} (a q .) + C u (s)

Join BYJU'S Learning Program