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Question

Determine whether the given function is even or odd sin5x+2tan3x

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Solution

f(x)=sin5x+2tan3x
f(x)=sin5(x)+2tan3(x)
f(x)=(sin5x+2tan3x) (Since, sine and tangent both are odd functions.)
f(x)=f(x)
Therefore, f(x) is odd.

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