Question

Determine whether the values given against each of the quadratic equation are the roots of the equation.
$2m^2-5m=0,m=2,\frac{5}{2}$

Answer 1

$2m^2-5m=0$

given values of m$=2,\frac{5}{2}$

when $m=2\to 2\left(2^2\right)-5\left(2\right)=8-10=-2$ does not satisfy the equation.

when $x=\frac{5}{2}\to 2{\left(\frac{5}{2}\right)}^2-5\left(\frac{5}{2}\right)=\frac{25}{2}-\frac{25}{2}=0$ satisfies the equation.

Therefore $m=\frac{5}{2}$ is only the root of given equation.