The correct option is A (i)
Let g(x)=x−2
Now,g(x)=x−2
=>x−2=0
=>x=2
(i)
Let p(x)=3x2+6x−24
Now, g(x) is a factor p(x) if p(2)=0
Thus, p(2)
=3(2)2+6(2)−24
=12+12−24
=0
Thus, g(x) is a factor of p(x)
(ii)
Let p(x)=4x2+x−2
Now, g(x) is a factor p(x) if p(2)=0
Thus, p(2)
=4(2)2+2−2
=16
≠0
Thus, g(x) is not a factor of p(x)
So, (i) is the factor of x−2