Determine $x$ , when $y = 40^{o}$ .

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Solution

from figure $y + 2 x = 180^{\circ}$
$⟹ 40^{\circ} + 2 x = 180^{\circ}$
$⟹ 2 x = 140^{\circ} ⟹ x = 70^{\circ}$

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