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Heavy Water

Deuteromethan...

Question

Deuteromethane can be prepared if $D_{2} O$ reacts with:

A l_{4} C_{3}

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C a C_{2}

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both A and B

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none of the above

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Solution

The correct option is A $A l_{4} C_{3}$
On hydrolysis of $A l_{4} C_{3}$ methane forms, similarly $D_{2} O$ reacts with $A l_{4} C_{3}$ and deuteromethane forms as the product.

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Similar questions

C a C_{2}, A l_{4} C_{3} a n d M g_{2} C_{3}

H_{2} O

25^{o} C .

C a C_{2} (s) + 2 H_{2} O (l) \to C a (O H)_{2} (s) + C_{2} H_{2} (g)

A l_{4} C_{3} (s) + 12 H_{2} O (l) \to 4 A l (O H)_{3} (s) + 3 C H_{4} (g)

M g_{2} C_{3} (s) + 4 H_{2} O (l) \to 2 M g (O H)_{2} (s) + C H_{3} - C \equiv C H (g)

C a C_{2} + 2 D_{2} O \to C_{2} D_{2} + C a (O D)_{2}

S O_{3} + D_{2} O \to D_{2} S O_{4}

A l_{4} C_{3} + 12 D_{2} O \to 3 C D_{4} + 4 A l (O D)_{3}

C_{2} D_{2} + O_{2} \to C O_{2} + D_{2} O

C D_{4} + O_{2} \to C O_{2} + D_{2} O

C a C_{2}, S O_{3} & A l_{4} C_{3}

3 : 2 : 1

O_{2}

D_{2} O

D_{2} O

C a C_{2}

A l_{4} C_{3}

Which of the following on hydrolysis can give methane

A) $A l_{4} C_{3}$ B) $B e_{2} C$ C) Ca $C_{2}$ D) $C H_{3} M g C l$

Which is not obtained when metal carbides react with H₂O?

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