Question

Deuteron and $\alpha$-particle are put $1A^o$ apart in air. Magnitude of intensity of electric field due to deuteron of $\alpha$-particle is $\left(N/C\right)$

• A. $Zero$
• B. $2.88\times {10}^{11}N/C$
• C. $1.44\times {10}^{11}N/C$
• D. $5.76\times {10}^{11}N/C$

Answer 1

The correct option is C $1.44\times {10}^{11}N/C$

E$=9\times {10}^9\frac{q}{r^2}$
$=9\times {10}^9\frac{1.6\times {10}^{-19}}{(1\times {10}^{-10}{)}^2}=1.44\times {10}^{11}N/C$.