Devendra invested Rs.1,000 in the first year and Rs.1,400 in the second year.'Again in the third year he invested Rs.1800.
Thus his investment in each year forms an A.P.
Consider the A.P 1000,1400,1800,......
Here a=1000 and common difference =1400−1000=1800−1400=400
Sum of total amount Devendra invested =Sn
Sn=n2[2a+(n−1)d]
⇒ S12=122[2×1000+(12−1)×400]
⇒ S12=6[2000+11×400]
⇒ S12=6[2000+4400]
⇒ S12= Rs.38,400
Thus, the total amount he invested in 12 years is Rs.38400.