DF is equal to QR and ∠Q equals ∠D. Which is the closest criterion for congruency of triangles to prove the given two triangles are congruent?
A
ASA
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B
RHS
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C
SAS
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D
SSS
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Solution
The correct option is A ASA In triangles, △DFE and △QRP ∠D = ∠Q (given) DF = QR (given) ∠F = ∠R = 90∘ Therefore, by ASA criterion, △DFE and △QRP are congruent.