DF is equal to QR and $∠$ Q equals $∠$ D. Which is the closest criterion for congruency of triangles to prove the given two triangles are congruent?

ASA

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RHS

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SAS

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SSS

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Solution

The correct option is A ASA
In triangles, $△$ DFE and $△$ QRP
$∠$ D = $∠$ Q (given)
DF = QR (given)
$∠$ F = $∠$ R = 90 $^{\circ}$
Therefore, by ASA criterion, $△$ DFE and $△$ QRP are congruent.

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Similar questions

Two triangles are congruent if two angles and the side included between them in one of the triangles are equal to the two angles and the side included between them of the other triangle. This is known as the

a) RHS congruence criterion
b) ASA congruence criterion
c) SAS congruence criterion
d) AAA congruence criterion

Question 46

By which congruency criterion, the two triangles in the given figure are congruent?

a) RHS
b) ASA
c) SSS
d) SAS

Q. DF is equal to QR and

∠

Q equals

∠

D. Which is the closest criterion for congruency of triangles to prove the given two triangles are congruent?

Q. In triangles ABC and PQR, ∠A = ∠P, AB = PQ and ∠B = ∠Q; then by which congruency criterion are these two triangles congruent?

Q. Which criteria for congruency of triangles can be used to prove the given two triangles are congruent?

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DF is equal to QR and ∠Q equals ∠D. Which is the closest criterion for congruency of triangles to prove the given two triangles are congruent?

The correct option is A ASAIn triangles, △DFE and △QRP ∠D = ∠Q (given) DF = QR (given) ∠F = ∠R = 90∘ Therefore, by ASA criterion, △DFE and △QRP are congruent.

DF is equal to QR and $∠$ Q equals $∠$ D. Which is the closest criterion for congruency of triangles to prove the given two triangles are congruent?

The correct option is A ASA
In triangles, $△$ DFE and $△$ QRP
$∠$ D = $∠$ Q (given)
DF = QR (given)
$∠$ F = $∠$ R = 90 $^{\circ}$
Therefore, by ASA criterion, $△$ DFE and $△$ QRP are congruent.