$\frac{1}{3} r d$ part of the length of a bamboo is coloured red and $\frac{1}{5} t h$ part of its coloured green and the remaining $14 m$ is coloured yellow. Find the length of the bamboo.

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Solution

Given, $\frac{1}{3} r d$ part of the length of bamboo is colored red and $\frac{1}{5} t h$ part of its colored green.

Remaining part of the bamboo is $1 - \frac{1}{3} - \frac{1}{5} = \frac{7}{15}$ .

Then according to the problem we've,

$\frac{7}{15}$ part of the bamboo $= 14$ m

Then the length of the bamboo is $= \frac{15}{7} \times 14 = 30$ m.

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13rd part of the length of a bamboo is coloured red and 15th part of its coloured green and the remaining 14m is coloured yellow. Find the length of the bamboo.

Given, 13rd part of the length of bamboo is colored red and 15th part of its colored green.Remaining part of the bamboo is 1−13−15=715.Then according to the problem we've,715 part of the bamboo =14 mThen the length of the bamboo is =157×14=30 m.

$\frac{1}{3} r d$ part of the length of a bamboo is coloured red and $\frac{1}{5} t h$ part of its coloured green and the remaining $14 m$ is coloured yellow. Find the length of the bamboo.