1-cos - -sin 2 - sin - 1-cos- -cot-

1+cosθ sin^2θ/sinθ(1+cosθ)=1 sin^2θ+cosθ/sinθ(1+cosθ) = cos^2θ+cosθ/sinθ(1+cosθ) [∵ 1 sin^2θ=cos^2θ] = cos θ #160;(cosθ+1)/sinθ(1+cosθ) = ...

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Domain

1+cos θ -sin ...

Question

$\frac{1 + c o s θ {- s i n}^{2} θ}{s i n θ (1 + c o s θ)} = c o t θ$

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Solution

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Similar questions

\frac{1 + c o s θ - s i n^{2} θ}{s i n θ (1 + c o s θ)} = c o t θ

Prove the following trigonometric identities:

$\frac{1 + c o s θ - s i n^{2} θ}{s i n θ (1 + c o s θ)} = c o t θ$

(c o s e c θ - c o t θ) \sqrt{\frac{1 + c o s θ}{1 - c o s θ}} = 1

\sqrt{\frac{1 + c o s θ}{1 - c o s θ}} = c o s e c θ + c o t θ

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