1111x-12-11x-12-111x-12-11x-12-x36- then x is equal to

The correct option is D 70 1111x+12+11x+12+111x+12+11x+12=x36 ⇒ 1 1 1 x+2 2x + + 1 x+2 2x #160; #160; + 1 1 x+2 2x + + 1 x+ ...

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Addition of Rational Numbers

1111x+12+11x+...

Question

$\frac{1}{\frac{1}{\frac{1}{\frac{1}{x} + \frac{1}{2}} + \frac{1}{\frac{1}{x} + \frac{1}{2}}} + \frac{1}{\frac{1}{\frac{1}{x} + \frac{1}{2}} + \frac{1}{\frac{1}{x} + \frac{1}{2}}}} = \frac{x}{36}$ , then $x$ is equal to

70

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72

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36

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68

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Solution

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Similar questions

\int {\sqrt{2 x^{2} - 3 x + 1}}_{d x}

If $(x - \frac{1}{x}) = 6$ , then $(x^{2} + \frac{1}{x^{2}}) = ?$

(a) $36$
(b) $38$
(c) $32$
(d) $36 \frac{1}{36}$

x^{2} - x \sqrt{3} + 1 = 0

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a_{0} + a_{3} + a_{6} + . . . . + a_{36}

{t a n}^{- 1} \frac{x - 1}{x - 2} + {t a n}^{- 1} \frac{x + 1}{x + 2} = \frac{π}{4}

{t a n}^{- 1} \frac{x - 1}{x + 1} + {t a n}^{- 1} \frac{2 x - 1}{2 x + 1} = {t a n}^{- 1} \frac{23}{36}

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