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Byju's Answer
Standard X
Mathematics
Range of Trigonometric Ratios from 0 to 90 Degrees
1 sin 10 o -√...
Question
1
s
i
n
10
o
−
√
3
c
o
s
10
o
=
4
A
True
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B
False
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Solution
The correct option is
B
False
1
sin
10
∘
−
√
3
cos
10
∘
=
2
(
1
2
sin
10
∘
−
√
3
2
cos
10
∘
)
We know that
sin
30
∘
=
1
2
and
cos
30
∘
=
√
3
2
=
2
(
1
2
sin
10
∘
−
√
3
2
cos
10
∘
)
=
2
(
sin
30
∘
sin
10
∘
−
cos
30
∘
cos
10
∘
)
=
−
2
(
cos
30
∘
cos
10
∘
−
sin
30
∘
sin
10
∘
)
=
−
2
(
cos
(
30
+
10
)
)
=
−
2
cos
40
∘
≠
4
Hence the statement is false.
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