1 - tan2 A1 - 2 A is equal to

The correct option is A tan^2 A it can be written as #160; 1+tan ^2A1+^2A= ^2Acosec^2A=1cos ^2A1sin ^2A=sin ^2Acos ^2A=tan ^2A Therefore, Answer is ...

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Standard X

Mathematics

Trigonometric Identity- 2

1 + tan2 A1 +...

Question

$\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}$ is equal to

{tan}^{2} A

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{sec}^{2} A

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cos A

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sin A

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Solution

The correct option is A ${tan}^{2} A$
it can be written as
$\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A} = \frac{{sec}^{2} A}{{cosec}^{2} A} = \frac{\frac{1}{{cos}^{2} A}}{\frac{1}{{sin}^{2} A}} = \frac{{sin}^{2} A}{{cos}^{2} A} = {tan}^{2} A$

Therefore, Answer is ${tan}^{2} A$

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Similar questions

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\frac{sin A - cos A}{sin A + cos A} = tan 2 A - sec 2 A

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\frac{c o s a + s i n a}{c o s a - s i n a} = t a n 2 a + s e c 2 a

Q. Find

(cos A + sec A)^{2} + {(sin A + cosec A)}^{2} - {tan}^{2} A - {cot}^{2} A .

{(sin A + cos e c A)}^{2} + {(cos A + sec A)}^{2} = {tan}^{2} A + {cot}^{2} A + 7

(sin A + csc A)^{2} + (cos A + sec A)^{2} = 7 + {tan}^{2} A + {cot}^{2} A

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1+tan2A1+cot2A is equal to

The correct option is A tan2Ait can be written as 1+tan2A1+cot2A=sec2Acosec2A=1cos2A1sin2A=sin2Acos2A=tan2ATherefore, Answer is tan2A

$\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A}$ is equal to

The correct option is A ${tan}^{2} A$
it can be written as
$\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A} = \frac{{sec}^{2} A}{{cosec}^{2} A} = \frac{\frac{1}{{cos}^{2} A}}{\frac{1}{{sin}^{2} A}} = \frac{{sin}^{2} A}{{cos}^{2} A} = {tan}^{2} A$

Therefore, Answer is ${tan}^{2} A$