Question

$\frac{18}{81}÷\frac{36}{45}=$ $\frac{x}{18}$. Find x.

Answer 1

For the value of $x$, we have to solve the given equation:-

$\Rightarrow \frac{18}{81}÷\frac{36}{45}=\frac{x}{18}$ {Divide $36$ by $18$ we get $2$ &Divide $81$& $45$ both by $9$ we get}

$\Rightarrow \frac{18}{81}\times \frac{45}{36}=\frac{x}{18}$

$\Rightarrow \frac{5}{18}=\frac{x}{18}$ {Cancle $18$ both side}

$\therefore x=5$