2 /( 2x 3 ) #160; + 5 /( 2x 3 ) #160; ^ 2 = 3 / 3x 2 #160; ⇒ 2( 2x 3 ) +5 /( 2x 3 ) 2 = 3 /( 3x 2 ) #160; #160; 4x 6+5 /( 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition of Rational Expressions

22x-3+52x-32=...

Question

Solve $\frac{2}{2 x - 3} + \frac{5}{(2 x - 3)^{2}} = \frac{3}{3 x - 2}$ .

Open in App

Solution

$\frac{2}{(2 x - 3)} + \frac{5}{{(2 x - 3)}^{2}} = \frac{3}{3 x - 2} \Rightarrow \frac{2 (2 x - 3) + 5}{{(2 x - 3)}^{2}} = \frac{3}{(3 x - 2)} \frac{4 x - 6 + 5}{(3 - 2 x)} = \frac{3}{1}, 4 x - 1 = 3 (3 - 2 x) \Rightarrow 4 x - 1 = 9 - 6 x \Rightarrow 10 x = 10 ∴ x = 1$

Suggest Corrections

Similar questions

3 [\frac{3 x - 1}{2 x + 3}] - 2 [\frac{2 x + 3}{3 x - 1}] = 5; x \neq \frac{1}{3}, - \frac{3}{2}

\frac{x + 2}{(x + 1) (2 x + 3)} - \frac{2 x + 3}{(x + 1) (x + 2)} + \frac{3 x + 5}{(2 x + 3) (x + 2)}

$\frac{(2 x - 1)}{3} \geq \frac{(3 x - 2)}{3} \geq \frac{(3 x - 2)}{4} - \frac{(2 - x)}{5}$

2 x^{5} - 7 x^{4} - 2 x^{3} + 18 x^{2} - 3 x - 8

x^{3} - 2 x^{2} + 1

(2 x^{3} - 3 x^{2} + 2 x - 3)

(3 x^{2} - 4 x + 1)

6 x^{5} - 17 x^{4} + 20 x^{3} - 20 x^{2} + 14 x - 3

Join BYJU'S Learning Program