$\frac{- 2}{3} \times (\frac{1}{4})^{- 3}$ equals to:

\frac{- 128}{3}

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\frac{1}{4}

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1

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16

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Solution

The correct option is A $\frac{- 128}{3}$
$\frac{- 2}{3} \times {(\frac{1}{4})}^{- 3} = \frac{- 2}{3} \times {(\frac{4}{1})}^{3} = \frac{- 2 * 4^{3}}{3} = \frac{- 128}{3}$

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\infty

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